0=(-4.9t^2)+25t

Solution for 0=(-4.9t^2)+25t equation:

0=(-4.9t^2)+25t

We move all terms to the left:

0-((-4.9t^2)+25t)=0

We add all the numbers together, and all the variables

-((-4.9t^2)+25t)=0


We calculate terms in parentheses: -((-4.9t^2)+25t), so:

(-4.9t^2)+25t

We get rid of parentheses

-4.9t^2+25t

Back to the equation:

-(-4.9t^2+25t)


We get rid of parentheses

4.9t^2-25t=0

a = 4.9; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·4.9·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*4.9}=\frac{0}{9.8}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*4.9}=\frac{50}{9.8}
=5+1/9.8
$